Hi,
What I do now, is choose all Article elements that contain info="main"
and info="sub" attributes and then sort everything by state="n"
attribute.
An Article cannot have two info attributes, thus the above condition can never
be true in XML.
Is it possible to implement an sorting option that enables Article
elements where filter="food" to be placed on the top of the Article
list, that is giving them higher priority in sort than the previous
value of state="n".
so the XML output will look like:
<?xml version="1.0"?>
<Documents>
<Document title="1" chapter="i" href="file1.xml" filter="food">
<Article title="1.2" info="main" filter="food"/>
<Article title="1.3" info="main" filter="drink"
state="2"/>
</Document>
<Document title="2" chapter="ii" href="file2.xml"
filter="drink">
<Article title="2.2" info="main" filter="food"/>
<Article title="2.1" info="main"
filter="drink" state="1"/>
</Document>
<Document title="4" chapter="2" href="file2.xml" filter="">
<Article title="3.2" info="main" filter="food"/>
</Document>
</Documents>
<xsl:template match="Documents">
<xsl:copy>
<xsl:apply-templates select="Document[Article/@info = 'main' and
Article/@info = 'sub']"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Document">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:for-each select="Article[(_at_)info = 'main']">
<xsl:sort select="@filter ='food'" data-type="number"
order="descending"/>
<xsl:sort select="@state" data-type="number"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
I'm not sure exactly how you wanted the info attribute handled, because you
desired output doesn't use Articles with "sub" info. Anyhow, this produces the
desired output. The
<xsl:sort select="@filter ='food'" data-type="number" order="descending"/>
sort condition basically works so that the "@filter = 'food'" expression will
either return boolean true or false, which will be cast to number 1 or 0,
respectively, and that gives you the sort key value.
Cheers,
Jarno - Lisa Lashes: Hard Mix