Hi,
Most probably the second predicate, i.e.
<xsl:for-each select="Article[(_at_)info = 'main']">
only processes the main ones.
Cheers,
Jarno - Velvet Acid Christ: Futile (Resisted mix by Funker Vogt)
-----Original Message-----
From: ext Mike G [mailto:row(_dot_)filter(_at_)gmail(_dot_)com]
Sent: 15 October, 2004 11:16
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] How to sort?
How do I get Only one chapter e.g. chapter="2" instead of
getting all chapters
in kombination with implementation above?
-Mike
On Fri, 15 Oct 2004 10:07:34 +0200, Mike G
<row(_dot_)filter(_at_)gmail(_dot_)com> wrote:
Yeah, this works with some modification.
<xsl:apply-templates select="Document[Article/@info = 'main' or
Article/@filter = 'food']"/>
thanx!
-Mike
On Thu, 14 Oct 2004 15:06:16 +0300,
jarno(_dot_)elovirta(_at_)nokia(_dot_)com
<jarno(_dot_)elovirta(_at_)nokia(_dot_)com> wrote:
Hi,
What I do now, is choose all Article elements that
contain info="main"
and info="sub" attributes and then sort everything by state="n"
attribute.
An Article cannot have two info attributes, thus the
above condition can never be true in XML.
Is it possible to implement an sorting option that
enables Article
elements where filter="food" to be placed on the top of
the Article
list, that is giving them higher priority in sort than
the previous
value of state="n".
so the XML output will look like:
<?xml version="1.0"?>
<Documents>
<Document title="1" chapter="i" href="file1.xml"
filter="food">
<Article title="1.2" info="main" filter="food"/>
<Article title="1.3" info="main" filter="drink"
state="2"/>
</Document>
<Document title="2" chapter="ii" href="file2.xml"
filter="drink">
<Article title="2.2" info="main"
filter="food"/>
<Article title="2.1" info="main"
filter="drink" state="1"/>
</Document>
<Document title="4" chapter="2" href="file2.xml"
filter="">
<Article title="3.2" info="main" filter="food"/>
</Document>
</Documents>
<xsl:template match="Documents">
<xsl:copy>
<xsl:apply-templates select="Document[Article/@info
= 'main' and Article/@info = 'sub']"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Document">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:for-each select="Article[(_at_)info = 'main']">
<xsl:sort select="@filter ='food'"
data-type="number" order="descending"/>
<xsl:sort select="@state" data-type="number"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
I'm not sure exactly how you wanted the info attribute
handled, because you desired output doesn't use Articles with
"sub" info. Anyhow, this produces the desired output. The
<xsl:sort select="@filter ='food'" data-type="number"
order="descending"/>
sort condition basically works so that the "@filter =
'food'" expression will either return boolean true or false,
which will be cast to number 1 or 0, respectively, and that
gives you the sort key value.
Cheers,
Jarno - Lisa Lashes: Hard Mix
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