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Re: how select all siblings?

2004-10-12 13:43:27
Hardy,

    Have you tried $section_legislators/legistor ? 

Regards,
Kenneth

On Tue, 12 Oct 2004 14:42:17 -0400, Hardy Merrill
<hmerrill(_at_)dhcr(_dot_)state(_dot_)ny(_dot_)us> wrote:
Here's a snippet from an XSL style sheet:

<xsl:template name="display_section">
        <xsl:param name="section_legislators"/>

        <tr><td colspan="4">Count section_legislators:<xsl:value-of
select="count($section_legislators)"/></td></tr>
        <xsl:variable name="sorted_legislators">
                <xsl:for-each select="$section_legislators">
                        <xsl:sort select="district_type" />
                        <xsl:sort select="district_no"
data-type="number" />
                        <xsl:sort select="legislator_active_date"
data-type="number" order="descending" />
                        <xsl:copy-of select="."/>
                </xsl:for-each>
        </xsl:variable>
        <tr><td colspan="4">Count sorted_legislators: <xsl:value-of
select="count(msxsl:node-set($sorted_legislators))"/></td></tr>


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