Thanx!
In this example, where I only user Muenchian method to group, elements where
info-attribute doesn't contains anything are also displayed, but not needed.
How do I get rid of those elements here?
<?xml version='1.0' encoding='UTF-8'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:key name="by-info" match="Article" use="@info"/>
<xsl:template match="/Documents">
<Documents>
<xsl:for-each select="Document/Article[count(.|key('by-info',
@info)[1])=1]">
<Document name="{(_at_)info}">
<xsl:copy-of select="key('by-info', @info)"/>
</Document>
</xsl:for-each>
</Documents>
</xsl:template>
</xsl:stylesheet>
Thank you!
_m
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian
Method?
Date: Thu, 7 Oct 2004 13:13:10 +0100
You get
$ saxon filter.xml filter.xsl
<?xml version="1.0" encoding="UTF-8"?>
<Documents>
<Document name="sub">
<Article title="1.1" info="sub" filter="food"/>
</Document>
<Document name="main">
<Article title="1.2" info="main" filter="food"/>
<Article title="2.2" info="main" filter="food"/>
</Document>
<Document name="child"/>
</Documents>
because of the different ways you filter.
on document you allow "" but in
<xsl:copy-of select="key('by-info',@info)[(_at_)filter=$filter]"/>
you don't.
I think that _is_ what you want, so in your for-each,
<xsl:for-each select="Document[(_at_)filter='' or
@filter=$filter]/Article[generate-id()=generate-id(key('by-info',@info)[(_at_)filter=''
or @filter=$filter])]">
you want to make sure that you always have at least one eleemnt in the
key that really has the filter value and not just "" so that
<xsl:copy-of select="key('by-info',@info)[(_at_)filter=$filter]"/>
always produces something.
you can do that by making the filters on the key() match,
delete @filter='' or
<xsl:for-each select="Document[(_at_)filter='' or
@filter=$filter]/Article[generate-id()=generate-id(key('by-info',@info)[(_at_)filter=$filter])]">
and you get
$ saxon filter.xml filter.xsl
<?xml version="1.0" encoding="UTF-8"?>
<Documents>
<Document name="sub">
<Article title="1.1" info="sub" filter="food"/>
</Document>
<Document name="main">
<Article title="1.2" info="main" filter="food"/>
<Article title="2.2" info="main" filter="food"/>
</Document>
</Documents>
David
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