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Re: document() path relative to current document

2004-11-23 09:52:25
I tried it out. Here is my code snippet. As @href commes from the attribute
value of an HTML <a i still think it is only a string.
...
                        <!-- Get expected type of related content -->
                        <xsl:variable name="expected-type" 
select="normalize-space(@type)"/>     
      
 
                        <!-- For each <A> pointing to related content... -->
                        <xsl:for-each select="a">
                                <xsl:variable name="external-doc" 
select="document(@href,/)"/>
                                <xsl:variable name="external-type" 
select="normalize-space($external-doc/kiwi-contenttype/@name)"/>
                                
                                <xsl:choose>
                                        <xsl:when test="$expected-type = 
$external-type">
                                                <kiwi-link url="{(_at_)href}" />
                                        </xsl:when>
...
  Thanks for your quick reply. But the way you describe it, can not work,
  because the document function needs a string to tell which document to
  access. I tried it out and i didn't work.

the document function does not require a string.

document() takes either a string or a node set, the behaviour is
different in the two cases. If you give it a string (eg using concat())
then the base URI of the stylesheet is used. If you give it a node set
eg @href then the base uri of the node is used.
in either case you can override the defualt base uri by giving a second
argument to document eg
document(concat(zzzz,zzzz),/)
will use the base uri of the / node of the source rather than the
stylesheet.


David

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