Hello again,
I have looked at Jeni's solution, and I would very much like to implement
this solution.
Unfortunately, I am not good enough with keys yet, and my problem is a
little more complicated than my first example.
I will try to scetch a more complicated problem, and I hope that someone can
show me how to this can be solved.
I do not know if one pass is possible in XSLT 1.0....?
Again my thanks for anybody who takes the time to look at this.
Regards,
Ragulf Pickaxe
<!-- Data before first pass in two-pass solution -->
<?xml version="1.0">
<Root>
<Elem GroupID="A" Type1="1" Type2="0" Order="7">A7</Elem>
<Elem GroupID="A" Type1="1" Type2="0" Order="5">A5</Elem>
<Elem GroupID="B" Type1="0" Type2="0" Order="4">B4</Elem>
<Elem GroupID="D" Type1="0" Type2="1" Order="2">D2</Elem>
<Elem GroupID="C" Type1="1" Type1="1" Order="4">C4</Elem>
<Elem GroupID="B" Type1="0" Type2="0" Order="3">B3</Elem>
<Elem GroupID="A" Type1="1" Type2="0" Order="2">A2</Elem>
<Elem GroupID="C" Type1="1" Type1="1" Order="1">C1</Elem>
<Elem GroupID="D" Type1="0" Type2="1" Order="4">D4</Elem>
<Elem GroupID="B" Type1="0" Type2="0" Order="2">B2</Elem>
<Elem GroupID="D" Type1="0" Type2="1" Order="3">D3</Elem>
<Elem GroupID="A" Type1="1" Type2="0" Order="1">A1</Elem>
</Root>
<!-- Data after first pass in two-pass solution (sorted by @GroupID and
@Order) -->
<?xml version="1.0">
<Root>
<Elem GroupID="A" Type1="1" Type2="0" Order="1">A1</Elem>
<Elem GroupID="A" Type1="1" Type2="0" Order="2">A2</Elem>
<Elem GroupID="A" Type1="1" Type2="0" Order="5">A5</Elem>
<Elem GroupID="A" Type1="1" Type2="0" Order="7">A7</Elem>
<Elem GroupID="B" Type1="0" Type2="0" Order="2">B2</Elem>
<Elem GroupID="B" Type1="0" Type2="0" Order="3">B3</Elem>
<Elem GroupID="B" Type1="0" Type2="0" Order="4">B4</Elem>
<Elem GroupID="C" Type1="1" Type1="1" Order="1">C1</Elem>
<Elem GroupID="C" Type1="1" Type1="1" Order="4">C4</Elem>
<Elem GroupID="D" Type1="0" Type2="1" Order="2">D2</Elem>
<Elem GroupID="D" Type1="0" Type2="1" Order="3">D3</Elem>
<Elem GroupID="D" Type1="0" Type2="1" Order="4">D4</Elem>
</Root>
<?xml version="1.0">
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:param name="ChooseWhichType1First" select="'1'"/>
<xsl:template match="/">
<Output>
<xsl:apply-templates select="Root"/>
</Output>
</xsl:template>
<xsl:template match="Root">
<!-- The different types of Elem have to be in a certain order -
independent of GroupID -->
<xsl:apply-templates select="Elem[(_at_)Type1=$ChooseWhichType1First]"/>
<xsl:apply-templates
select="Elem[not(@Type1=$ChooseWhichType1First)][Type2='1']"/>
<xsl:apply-templates
select="Elem[not(@Type1=$ChooseWhichType1First)][Type2='0']"/>
<!-- In the two-pass solution I do not have to sort with the two sorts
below: -->
<!--
<xsl:sort select="@GroupID">
<xsl:sort select="@Order" data-type="number">
-->
<!-- I have an idea that I will need one key for each of the above
templates, but I do not know what to write, nor whether
my idea is even right (Jeni Tennison's solution provided at buttom of this
mail) -->
</xsl:template>
<xsl:template match="Elem">
<xsl:if test="not(preceding-sibling::Elem/@GroupID=current()/@GroupID)">
<Group><xsl:value-of select="@GroupID"/></Group>
</xsl:if>
<xsl:value-of select="."/> -
</xsl:template>
</xsl:stylesheet>
Output:
<Output>
<Group>A</Group>A1 - A2 - A5 - A7 -
<Group>C</Group>C1 - C4 -
<Group>D</Group>D2 - D3 - D4 -
<Group>B</Group>B2 - B3 - B4 -
</Output>
(Summary: I would very much like to get the same output in one go with the
unsorted input (the first pass) - if this is
possible).
Jeni Tennison's solution, which would if there was no @Type1 and @Type2 to
consider:
<xsl:key name="elems" match="Elem" use="@GroupID" />
<xsl:template match="Root">
<xsl:for-each select="Elem[generate-id(.) =
generate-id(key('elems', @GroupID)[1])]">
<Group><xsl:value-of select="@GroupID" /></Group>
<xsl:for-each select="key('elems', @GroupID)">
<xsl:sort select="@Order" data-type="number" />
<xsl:value-of select="." /> -
</xsl:for-each>
</xsl:for-each>
</xsl:template>
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