Hello all,
I seem to be caught on trying to sort something while at the same time
grouping them.
In the first input (see below), I have no problems, but the second gives me
problems in the current solution.
The problem seems that I get the nodes in sorted order, but the test on the
previous sibling goes to the document order.
How do I make the test so that I can group these elements, and still retain
the sorted order?
Thank you very much in advance!
Ragulf Pickaxe
<?xml version="1.0">
<Root> <!-- Input 1 -->
<Elem GroupID="A" Order="1">A1</Elem>
<Elem GroupID="A" Order="2">A2</Elem>
<Elem GroupID="B" Order="4">B4</Elem>
<Elem GroupID="A" Order="5">A5</Elem>
<Elem GroupID="C" Order="1">C1</Elem>
<Elem GroupID="B" Order="7">A7</Elem>
</Root>
<?xml version="1.0">
<Root> <!-- Input 2 -->
<Elem GroupID="A" Order="7">A7</Elem>
<Elem GroupID="A" Order="5">A5</Elem>
<Elem GroupID="B" Order="4">B4</Elem>
<Elem GroupID="A" Order="2">A2</Elem>
<Elem GroupID="C" Order="1">C1</Elem>
<Elem GroupID="B" Order="1">A1</Elem>
</Root>
<?xml version="1.0">
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<Output>
<xsl:apply-templates select="Root"/>
</Output>
</xsl:template>
<xsl:template match="Root">
<xsl:apply-templates select="Elem">
<xsl:sort select="@GroupID">
<xsl:sort select="@Order" data-type="number">
</xsl:apply-templates>
</xsl:template>
<xsl:template match="Elem">
<xsl:if test="not(preceding-sibling::Elem/@GroupID=current()/@GroupID)">
<Group><xsl:value-of select="@GroupID"/></Group>
</xsl:if>
<xsl:value-of select="."/> -
</xsl:template>
</xsl:stylesheet>
Output from input 1:
<Output>
<Group>A</Group>A1 - A2 - A5 - A7 -
<Group>B</Group>B4 -
<Group>C</Group>C1 -
</Output>
Output from input 2
<Output>
A1 - A2 - A5 - <Group>A</Group>A7 -
<Group>B</Group>B4 -
<Group>C</Group>C1 -
</Output>
(Summary: I would very much like to get second output to be the same as the
first output - I hope that this is possible).
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