Yes. Han (thank you) provided the following solution, which inserts a <row>
after each time/currency combination but it is not exactly the end result
I'd like to reach :
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method='xml'
indent='no' omit-xml-declaration='yes'/>
<xsl:template match='/'>
<x>
<xsl:apply-templates select='//Cube[not(*)]'/>
</x>
</xsl:template>
<xsl:template match='Cube'>
<row>
<time><xsl:value-of select="../@time"/></time>
<xsl:element name="{(_at_)currency}"><xsl:value-of
select="@rate"/></xsl:element>
</row>
</xsl:template>
</xsl:stylesheet>
Result :
- <x>
- <row>
<time>2004-11-19</time>
<USD>1.302</USD>
</row>
- <row>
<time>2004-11-19</time>
<JPY>134.97</JPY>
</row>
- <row>
The end result would be something like :
Result :
- <x>
- <row>
<time>2004-11-19</time>
<USD>1.302</USD>
<JPY>134.97</JPY>
</row>
- <row>
<time>2004-11-18</time>
...
Subject: RE: [xsl] Attribute to elements conversion, "preserving "and
simplifying hierarchy, insertion of new element
From: "Joe Heidenreich" <HeidenreichJ(_at_)xxxxxxxx>
Date: Fri, 19 Nov 2004 11:38:04 -0500
Do you want the <Row> to appear for each date?
Jeni has a great example on how to add hierarchy to a flat structure. You
can
view that here:
http://www.biglist.com/lists/xsl-list/archives/200012/msg00175.html
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