The typical way of alternating the background color of every other row
in an HTML table is something like this:
<xsl:for-each select="msxsl:node-set($sorted_legislators)">
<tr>
<xsl:if test="position() mod 2 = 0">
<xsl:attribute
name="bgcolor">#eeeeee</xsl:attribute>
</xsl:if>
------------------------------------
My situation is this - the for-each is based on legislators sorted by
district - here's a sample (not real) xml to illustrate:
<legislators>
<legislator>
<name>Joe</name>
<district_id>1</district_id>
</legislator>
<legislator>
<name>Bob</name>
<district_id>2</district_id>
</legislator>
<legislator>
<name>Pete</name>
<district_id>2</district_id>
</legislator>
</legislators>
There will be one *or more* legislators for each district. Instead of
alternating the background color for every *legislator*, I want to
alternate the background color for every *district*. In other words, I
want Joe in district_id 1 to have white background, but I want both Bob
and Pete in district_id 2 to have a gray background. But since I can't
change the value of a variable (can't increment a counter), I don't know
what I can base the bgcolor alternation on.
The xsl:for-each is based on a select of a variable containing all
legislators sorted by district.
I know there is probably an easy way to do this, but I don't know it.
Help!
Thanks.
Hardy Merrill
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--