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Omitting default namespace in the output - XSLT 2.0

2004-12-20 06:51:54
Hi,

Given an example input like:

<?xml version="1.0" encoding="UTF-8"?>
<norm xmlns="myDefaultNamespace">
        <table>
                <row>
                        <cell>My Table</cell>
                </row>
        </table>
</norm>

I searched for an easy way to get output data, 
which is not associated to my default namespace any more,
with the help of <xsl:copy-of> in XSLT 2.0
I hoped that the attribute "copy-namespaces" set to "no" would help me
here,
but unfortunately I had no luck with Saxon 8.1.1

My output still looks like 

<table>
        <row xmlns="myDefaultNamespace">
                <cell>My Table</cell>
        </row>
</table>


XSLT:
=====

        <xsl:template match="ln:table">
                <table>
                        <xsl:copy-of select="node() | @*"
copy-namespaces="no"/>
                </table>
        </xsl:template>


Thanks in advance for your input!

wbr,
Roman
_______________________________________

Roman Huditsch
IT and Electronic Publishing
LexisNexis ARD Orac 
Marxergasse 25
1030 Vienna
Austria 
ph: +43-1-534 52-1514
f: +43-1-534 52-140
e-mail roman(_dot_)huditsch(_at_)lexisnexis(_dot_)at
www.lexisnexis.at
 
 

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