Hi,
Given an example input like:
<?xml version="1.0" encoding="UTF-8"?>
<norm xmlns="myDefaultNamespace">
<table>
<row>
<cell>My Table</cell>
</row>
</table>
</norm>
I searched for an easy way to get output data,
which is not associated to my default namespace any more,
with the help of <xsl:copy-of> in XSLT 2.0
I hoped that the attribute "copy-namespaces" set to "no" would help me
here,
but unfortunately I had no luck with Saxon 8.1.1
My output still looks like
<table>
<row xmlns="myDefaultNamespace">
<cell>My Table</cell>
</row>
</table>
XSLT:
=====
<xsl:template match="ln:table">
<table>
<xsl:copy-of select="node() | @*"
copy-namespaces="no"/>
</table>
</xsl:template>
Thanks in advance for your input!
wbr,
Roman
_______________________________________
Roman Huditsch
IT and Electronic Publishing
LexisNexis ARD Orac
Marxergasse 25
1030 Vienna
Austria
ph: +43-1-534 52-1514
f: +43-1-534 52-140
e-mail roman(_dot_)huditsch(_at_)lexisnexis(_dot_)at
www.lexisnexis.at
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