Hi,
From: "Karl Stubsjoen" <karl(_at_)meetscoresonline(_dot_)com>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: FW: [xsl] Siblings
Date: Tue, 14 Dec 2004 11:53:58 -0700
Woops, correction to 2nd "IF the offset were" result below: should result
in "GRAPE", corrected with [GRAPE] below.
-----Original Message-----
From: Karl Stubsjoen [mailto:karl(_at_)meetscoresonline(_dot_)com]
Sent: Tuesday, December 14, 2004 11:49 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Siblings
I need to offset a sibling match for an offset of X. Example:
<elements>
<element item="1">APPLE</element>
<element item="2">ORANGE</element>
<element item="3">GRAPE</element>
<element item="4">WATERMELON</element>
<element item="5">CRANBERRY</element>
</elements>
If the offset were 0, then the result would be "APPLE", if the offse were
2,
then the result would be "ORANGE" -correction- [GRAPE].
Well, corrected here.
The template is always applied in order of the item, but the look up is
based on this offset value.
So, the big challenge: if the current item was 5 and the offset was 2,
then
the result would be "ORANGE".
What about the above. Shouldn't it be "GRAPE" as well?
I am not sure whether I have understood it clearly, but what about
using the following :-
<xsl:value-of select="/elements/element[(_at_)item = ($offset+1)]" />
Cheers.
Arun
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