Use:
channel[6 > id or id='P'] [6 > $n and $hasP]
|
channel[6 > id] [not(6 > $n and $hasP)]
Of course, in XPath 2.0 one can simply use a conditional expression:
if(expression)
then expression
else expression
Cheers,
Dimitre Novatchev.
On Thu, 20 Jan 2005 04:13:25 +1000,
r(_dot_)moe(_at_)student(_dot_)qut(_dot_)edu(_dot_)au
<r(_dot_)moe(_at_)student(_dot_)qut(_dot_)edu(_dot_)au> wrote:
How can I conditionaly assign a node-set to my variable?
Variable needs to have local scope.
Obviously I can't use <xsl:value-of.../>.
I get the error message:
"Reference to variable or parameter 'firstTableRows' must
evaluate to a node list."
Code:
<xsl:variable name="firstTableRows">
<xsl:choose>
<xsl:when test="6>$n and $hasP">
<xsl:value-of select="channel[6>id or id='P']"/>
</xsl:when>
<xsl:when test="6>$n">
<xsl:value-of select="channel[6>id]"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="channel[6>id]"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
Thanks,
Roy
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