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Re: Comparing node for identity using union

2005-01-19 12:08:29
Neverthless, just for the record, please note

       Sarissa.setXslParameter(xslDoc, "pos", pos+"");
       xml.transformNodeToObject(xslDoc, xmlResult);   ----> Works OK

       Sarissa.setXslParameter(xslDoc, "pos", pos);
       xml.transformNodeToObject(xslDoc, xmlResult);   ----> DOES NOT

       processor.setParameter(null, "pos", pos);            
       var xmlResult = processor.transformToDocument(xmlDoc);     
----> Works OK

       processor.setParameter(null, "pos", pos+"");
       var xmlResult = processor.transformToDocument(xmlDoc);     
----> DOES NOT


Works OK = $pos is recognized as a number so (//Menu)[$pos] gives the
Menu as position $pos

DOES NOT =  $pos is NOT recognized as a number so (//Menu)[$pos] gives
ALL the Menu  nodes, as just //Menu does.




On Wed, 19 Jan 2005 18:10:20 -0000, Michael Kay <mike(_at_)saxonica(_dot_)com> 
wrote:

The $pos is defined like

  <xsl:param name="pos" select="0"/>

That's certainly a number

I think it's only a number as long as it doesn't get overridden - as
soon as you pass in the value a parameter it becomes a string.

Of course: I missed that.

Shows how useful it is to declare your types in XSLT 2.0.

Michael Kay
http://www.saxonica.com/

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