this line gets the correct subtotal sum based on a group, so considered
removing the sum and placing
in a for-each would
somehow have it display correctly in the grid. This does not work. What happens
is the
correct subtotal is displayed on each line, instead of once per group.
<xsl:value-of select="format-number(sum(../Trade[Customer=
current()/Customer]/Step),'###,###,###,##0')"/></b></td>
is there a more specific grouping idea which addresses the placement of the
correctly
summed subtotal amount?
Thanks,
Dmitri
-----Original Message-----
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Sent: Jan 7, 2005 11:12 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] using preceding-sibling to display subtotal row
There are a list of elements, and the following code is
trying to create a new row to display subtotals.
There might be any number of Customer rows. Is there a way to
check if I've reached the last customer, and then
insert the subtotal row? The following code is inserting on
every row, instead of the last.
Sounds like a classic grouping problem - see
http://www.jenitennison.com/xslt/grouping
Don't think of this as "process all the rows, outputting a subtotal whenever
I reach the last customer in a group". Think of it as "process all the
groups; for each group, output each row in the group and then the subtotal
for the group".
Michael Kay
http://www.saxonica.com/
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