For the first i suppose you should use
extension-element-prefixes ="sql" on the stylesheet declaration.
On Fri, 07 Jan 2005 13:45:53 -0500, M Glenties
<mglenties(_at_)hotmail(_dot_)com> wrote:
Thank you everyone for your posts.
The solution from Charles Knell is close to what I need. The output has 2
problems:
1. The attribute xmlns:sql="urn:schemas-microsoft-com:xml-sql" is now
included with each element.
(FYI, the flat xml document I start with is created from an sql "for xml
auto" command in a template file launched by VB).
2. The data grouped in the new tags repeats after the tag (except for the
first element in the group).
For example, (snippet):
-------------------------------------
<ADDRESS>
<street xmlns:sql="urn:schemas-microsoft-com:xml-sql">35 Main
Street</street>
<city xmlns:sql="urn:schemas-microsoft-com:xml-sql">Moosejaw</city>
<country
xmlns:sql="urn:schemas-microsoft-com:xml-sql"y>Saskatchewan</country>
<postal_code
xmlns:sql="urn:schemas-microsoft-com:xml-sql">TOEOPO</postal_code>
</ADDRESS>
MoosejawSaskatchewanTOEOPO
------------------------------------
To clear up António's question, the following is needed as David said:
<xsl:template match="id|type|count|language">
<xsl:copy-of select="." />
</xsl:template>
but,
the following does not produce output:
<xsl:template
match="initial|lastname|city|country|postal_code|amount1|amount2|amount3" />
M Glenties.
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Group various elements with empty tags (flat XML
structure to hierarcial XML)
Date: Fri, 7 Jan 2005 14:29:18 GMT
Yes, but isn´t that the default template beahviour?
No, the default templates never produce elements in the result, they
just recursively process the children meaning that a stylesheet with no
templates will extract all the text content of an xml file, discarding
any element markup.
David
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