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RE: for-each and summing based on group
2005-01-05 16:12:29
Sorry, I should have made it clear that to use XSLT 2.0 you need an XSLT 2.0
processor. For most people this means using Saxon 8.x, though there are a
couple of other XSLT 2.0 processors becoming available.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: dmitrik(_at_)mindspring(_dot_)com
[mailto:dmitrik(_at_)mindspring(_dot_)com]
Sent: 05 January 2005 21:33
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] for-each and summing based on group
I'd rather use 1 if there is a simpler way to calculate
subtotals for this group.
If it is easier with 2, how is it invoked?
Thanks,
Dmitri
-----Original Message-----
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Sent: Jan 5, 2005 2:31 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] for-each and summing based on group
If you want maximum compatibility when running a 1.0
stylesheet under a 2.0
processor, leave the code completely unchanged - i.e. leave
version="1.0".
If you change it to say version="2.0" then you get more rigorous
type-checking: this won't allow implicit type conversions
such as comparing
a string to an integer. In this example you have to change
the code to make
it clear whether you want the integer converted to a string
or vice-versa.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: dmitrik(_at_)mindspring(_dot_)com
[mailto:dmitrik(_at_)mindspring(_dot_)com]
Sent: 05 January 2005 19:12
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] for-each and summing based on group
during a quick online search didn't see any example:
does 1.0 just change to 2.0 in the following?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
-----Original Message-----
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Sent: Jan 5, 2005 1:26 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] for-each and summing based on group
When changing the xsl from 1.0 to 2.0 there
were errors.
Is it simpler to do that, or use Muenchian grouping for the
Customer?
If you were saying that a stylesheet that worked under 1.0
didn't work under
a 2.0 processor, then this is unusual and it would be nice
to know the
details.
Michael Kay
http://www.saxonica.com/
<xsl:for-each select="Trade">
<xsl:sort select="Customer"/>
<tr class="r{position() mod 2}">
<td><xsl:value-of select="Customer"/> </td>
<td><xsl:value-of select="TradeId"/><xsl:text/></td>
<td><xsl:value-of select="Type"/><xsl:text/></td>
<td align="right">
<xsl:value-of select="format-number(sum(Step
[concat(substring(MinFlowDate,7),substring(MinFlowDate,1,2),su
bstring(MinFlowDate,4,2))>=
concat(substring($global,7),substring($global,1,2),substring($
global,4,2))]
[concat(substring(MinFlowDate,7),substring(MinFlowDate,1,2),su
bstring(MinFlowDate,4,2))<
concat(substring($global,7)+3,substring($global,1,2),substring
($global,4,2))]
/StepCharge)+ sum(Step
[concat(substring(MinFlowDate,7),substring(MinFlowDate,1,2),su
bstring(MinFlowDate,4,2))>=
concat(substring($global,7),substring($global,1,2),substring($
global,4,2))]
[concat(substring(MinFlowDate,7),substring(MinFlowDate,1,2),su
bstring(MinFlowDate,4,2))<
concat(substring($global,7)+3,substring($global,1,2),substring
($global,4,2))]
/StepSetoff) , '###,###,##0')"/>
</td>
</xsl:for-each>
Thanks,
Dmitri
-----Original Message-----
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Sent: Jan 5, 2005 4:50 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] for-each and summing based on group
First read up about standard grouping techniques such as
Muenchian grouping
at http://www.jenitennison.com/xslt/grouping
Computing a subtotal for each group is then a minor variant of the
technique: instead of merely iterating over the items in the
group using
xsl:for-each, you can assign the node-set comprising the
group to a
variable, and then sum over that using the sum() function.
Like all grouping problems, it's much easier in 2.0:
<xsl:for-each-group select="rows" group-by="columnA">
<xsl:apply-templates select="current-group()"/>
<subtotal><xsl:value-of
select="sum(current-group()/columnB)"/></subtotal>
</xsl:for-each-group>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: dsk [mailto:dmitrik(_at_)mindspring(_dot_)com]
Sent: 05 January 2005 04:09
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] for-each and summing based on group
within a for-each there might be various sets of values which
produce the
following grid, where val is equal to a number
a val val val
a val val val
a val val val
b val val val
b val val val
c val val val
c val val val
what is the best way to insert a sum line for the first
column a, one for b, and one for c.
is a nested for each needed? or checking to see if the
following value is
not equal to the preceding, then then summing?
thanks,
Dmitri
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