Joris Gillis wrote:
Tempore 23:01:31, die 02/21/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Nishi Bhonsle
<nishi(_dot_)bhonsle(_at_)oracle(_dot_)com>:
<xsl:template match="server">
<xsl:element name="drillOutDir">
<xsl:value-of select="abc:configuration/drillOutDir"/
</xsl:element>
<xsl:element name="started">
<xsl:copy-of select="@status[. = 'true' ]"/>
<xsl:value-of select="../abc:configuration/started"/>
</xsl:element>
</xsl:template>
<xsl:copy-of select="../abc:configuration/started/@status[. = 'true' ]"/>
But I actually don't understand why you create the 'drillOutDir' and
'started' elements inside a template that matches 'server' elements...
Hi:
I tried the above select statement in the xslt, but it still yields an
empty 'started' element in the output file.
ie
<xsl:element name="started">
<xsl:copy-of select="../abc:configuration/started/@status[. =
'true' ]"/>
</xsl:element>
If I create the 'drillOutDir' and the 'started' elements outside the
'server' elements template then I noticed that after applying the
transformation, the resultant output does not contain them AT ALL.
I tried the below, but neither worked. All the below templates result in
NOT containing the 'drillOutDir' and 'started' nodes in the output file.
<xsl:template match="abc:configuration/drillOutDir">
<xsl:element name="drillOutDir">
<xsl:value-of select="abc:configuration/drillOutDir"/>
</xsl:element>
</xsl:template>
<xsl:template match="abc:configuration">
<xsl:element name="drillOutDir">
<xsl:value-of select="abc:configuration/drillOutDir"/>
</xsl:element>
</xsl:template>
Can you suggest anything?
Thanks.
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