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Re: changing value of select in xsl:for-each

2005-02-21 10:12:26
That's seems too complicated for me to grasp...

BTW, i probably will have to do some work based on XForms, but i don't
know where to start. Can you give me some points to it?

Thanks.


On Mon, 21 Feb 2005 18:05:46 +0100, Prasad Akella 
<avlnprasad(_at_)web(_dot_)de> wrote:
i am not sure it works

my problem is like this

I have stylesheet A.xsl which is used to transform some Exam.xml into Xforms.

I am using another stylesheet B.xsl which takes A.xsl as input and transforms 
all the Xforms controls into Xhtml controls. the problem is iterating and 
displaying data in the xhtml controls from the Exam.xml which does not have 
any mention in B.xsl. i have this xsl:for-each select="Exam/Question" in 
A.xsl and i would like to dynamically change it to some variable assigned xml 
so that that the rest of the rendering is done. my problem is as of now since 
there is no Exam/Question all the cases inside the xsl:for-each are not 
rendered and are false. how to make them true and work is not gettign into my 
dumb head.

in case someone would like to know more i can put some code

kindly suggest and advice

with regards,
Prasad Akella

xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com schrieb am 21.02.05 17:18:14:

Just a hunch, but take a look at call-template with-param.


On Mon, 21 Feb 2005 15:56:17 +0100, Prasad Akella 
<avlnprasad(_at_)web(_dot_)de> wrote:
hello,

I have not yet been able to solve my problem. i would like to change the 
value of my select attribute in my xsl:for-each loop written in my first 
stylesheet when this first stylesheet is being used by another second 
stylesheet to change the controls. is this possible. i want to change 
because my first stylesheet is interacting with an xml from which the 
data is coming, but my second stylesheet is not interacting with that 
xml. i am using a variable to assign the source of that xml being used in 
first stylesheet so that it can be used where necessary in my second 
stylesheet but do not know how to change that in my xsl:for-each 
select="";

as of now i have

<xsl:for-each select="Exam/Question">

in my first stylesheet.

this i would like to change to

<xsl:for-each select="$srcxml//Question">

in my second stylesheet as i am using

<xsl:variable name="srcxml" select="document('Exam.xml')"/>

please suggest some idea or change. i am stuck with this and am not able 
to proceed.  actually it would be great if i can tell my second 
stylesheet that it has to use everywhere Exam.xml as the source whenever 
it encounters any xpath statement. but am not sure how totell it. please 
advise

with regards,
prasad akella
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