i am not sure it works
my problem is like this
I have stylesheet A.xsl which is used to transform some Exam.xml into Xforms.
I am using another stylesheet B.xsl which takes A.xsl as input and transforms
all the Xforms controls into Xhtml controls. the problem is iterating and
displaying data in the xhtml controls from the Exam.xml which does not have any
mention in B.xsl. i have this xsl:for-each select="Exam/Question" in A.xsl and
i would like to dynamically change it to some variable assigned xml so that
that the rest of the rendering is done. my problem is as of now since there is
no Exam/Question all the cases inside the xsl:for-each are not rendered and are
false. how to make them true and work is not gettign into my dumb head.
in case someone would like to know more i can put some code
kindly suggest and advice
with regards,
Prasad Akella
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com schrieb am 21.02.05 17:18:14:
Just a hunch, but take a look at call-template with-param.
On Mon, 21 Feb 2005 15:56:17 +0100, Prasad Akella
<avlnprasad(_at_)web(_dot_)de> wrote:
hello,
I have not yet been able to solve my problem. i would like to change the
value of my select attribute in my xsl:for-each loop written in my first
stylesheet when this first stylesheet is being used by another second
stylesheet to change the controls. is this possible. i want to change
because my first stylesheet is interacting with an xml from which the data
is coming, but my second stylesheet is not interacting with that xml. i am
using a variable to assign the source of that xml being used in first
stylesheet so that it can be used where necessary in my second stylesheet
but do not know how to change that in my xsl:for-each select="";
as of now i have
<xsl:for-each select="Exam/Question">
in my first stylesheet.
this i would like to change to
<xsl:for-each select="$srcxml//Question">
in my second stylesheet as i am using
<xsl:variable name="srcxml" select="document('Exam.xml')"/>
please suggest some idea or change. i am stuck with this and am not able to
proceed. actually it would be great if i can tell my second stylesheet
that it has to use everywhere Exam.xml as the source whenever it encounters
any xpath statement. but am not sure how totell it. please advise
with regards,
prasad akella
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