Tempore 19:07:22, die 02/14/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Wagstaff, Jason
<WagstaffJ(_at_)msx(_dot_)umsl(_dot_)edu>:
I have a text block that contains wherever the user wanted
it to look like a paragraph break. I don't any have control over the
input.
Any ideas on how can I replace with <br/>? Or better still, use
the 
 to identify the paragraphs and wrap each <p>paragraph</p>?
Hi,
Let's assume you have an XML with this node in it:
<text>Line1 Line2 other content</text>
And the desired output would be:
<div>
<p>Line1</p>
<p>Line2</p>
<p>other content</p>
</div>
This can be achieved by applying a stylesheet like this:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="text">
<div>
<xsl:call-template name="par"/>
</div>
</xsl:template>
<xsl:template name="par">
<xsl:param name="text" select="."/>
<p>
<xsl:value-of
select="substring-before(concat($text,' '),' ')"/>
</p>
<xsl:if test="contains($text,' ')">
<xsl:call-template name="par">
<xsl:with-param name="text">
<xsl:value-of
select="substring-after($text,' ')"/>
</xsl:with-param>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
"Scio me nihil scire" - Socrates
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