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Re: Get nodes with document() and applying templates to them

2005-02-14 07:22:38
I *do* want the resulting nodes to be REPlaced if there is menus of
MenuTipo=REP. That's why i'm using apply-templates.

Also, the second MenuData in the first tree as a key to the second
tree that i want to get.


What i'm saying is that if the second tree is like this (has REP's)

<Menu>
       <Menu_K>X00125</Menu_K>
       <MenuData/>
       <MenuTipo>TXT</MenuTipo>
       <MenuTitulo>Sub-Ambitos</MenuTitulo>
       <Menu>
               <Menu_K>X00126</Menu_K>
               <MenuData>X00130</MenuData>
               <MenuTipo>REP</MenuTipo>
               <MenuTitulo>Sub-Sub-Ambitos</MenuTitulo>
       </Menu>
</Menu>

then the REPlaces on this second tree dosen´t happen, i'll get something like

<Menu>
       <Menu_K>X00123</Menu_K>
       <MenuData/>
       <MenuTipo>TXT</MenuTipo>
       <MenuTitulo>Ambitos</MenuTitulo>
       <Menu>
               <Menu_K>X00125</Menu_K>
               <MenuData/>
               <MenuTipo>TXT</MenuTipo>
               <MenuTitulo>Sub-Ambitos</MenuTitulo>
       </Menu>
</Menu>

and i wanted to get the replaces for then too.

On Mon, 14 Feb 2005 06:13:58 -0800 (PST), David Carlisle
<davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:

If you just want a copy of the 2nd XML not to apply templates to it then
replace


<xsl:apply-templates
select="document('TreeMenu.xml')//Menu[Menu_K=current()/MenuData]/Menu"
/>

by

<xsl:copy-of
select="document('TreeMenu.xml')//Menu[Menu_K=current()/MenuData]/Menu"
/>

But I am slightly confused as you say you don't want copy-of and in teh
example that you posted, all  MenuData elements are empty, so the filter
Menu_K=current()/MenuData
is never going to be true as no Menu_K elements are empty.
thus you will get no nodes selected for the replacement.

David

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