If you just want a copy of the 2nd XML not to apply templates to it then
replace
<xsl:apply-templates
select="document('TreeMenu.xml')//Menu[Menu_K=current()/MenuData]/Menu"
/>
by
<xsl:copy-of
select="document('TreeMenu.xml')//Menu[Menu_K=current()/MenuData]/Menu"
/>
But I am slightly confused as you say you don't want copy-of and in teh
example that you posted, all MenuData elements are empty, so the filter
Menu_K=current()/MenuData
is never going to be true as no Menu_K elements are empty.
thus you will get no nodes selected for the replacement.
David
________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--