I haven't tried to study your particular problem, I'm afraid.
The general design approach to these problems is to
* start by defining the result tree that you want to produce
* for each element node in the result tree, write a template rule that
outputs that element
* then think about the conditions under which you want that template rule to
be fired, and write appropriate match patterns and/or apply-templates
instructions
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Huditsch Roman [mailto:Roman(_dot_)Huditsch(_at_)lexisnexis(_dot_)at]
Sent: 14 February 2005 13:28
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: AW: [xsl] Closing and reopening hierarchically
structured elements
Hi Michael,
Thanks very much for your reply.
Actually, I though about that before, but since I could not
imagine any other solution and being absolutly desperate,
I though this would be my last escape route...
My problem is that the table must appear at the same logical
position as before...
How can the grouping mechanism help me at this position?
Is there a simpler way in XSLT 2.0?
Thanks very much for your patience.
wbr,
Roman
-----Ursprüngliche Nachricht-----
Von: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Gesendet: Montag, 14. Februar 2005 13:42
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: RE: [xsl] Closing and reopening hierarchically
structured elements
The second step involves closing all ancestor elements before my
table.
Generating an <fo:block span="all">, including my table
markup within
and re-opening my closed ancestor elements (including all
attributes
defined before).
no, no! XSLT instructions write nodes to a tree, they don't
"open" and "close" elements. Writing a node is an indivisible
operation.
Read http://www.jenitennison.com/xslt/grouping, and
inwardly absorb...
Michael Kay
http://www.saxonica.com/
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