This isn't grouping, it's ungrouping.
<xsl:template match="root">
<doc>
<fragments>
<xsl:copy-of select=".//fragment">
</fragments>
</doc>
</xsl:template>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Robert Soesemann [mailto:rsoesemann(_at_)sapient(_dot_)com]
Sent: 09 February 2005 12:49
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Restructure via grouping
How can I do the following restructuring? Do I need to use grouping?
Inside and outside of my <doc> node there are <fragment> nodes. I want
to collect them all and place them insde a new <fragments> tag.
So for this input:
<root>
<doc>
<fragment pos="1"/>
<fragment pos="2"/>
<fragment pos="3"/>
</doc>
<fragment pos="4"/>
<fragment pos="5"/>
</root>
I would need the following output:
<root>
<doc>
<fragments>
<fragment pos="1"/>
<fragment pos="2"/>
<fragment pos="3"/>
<fragment pos="4"/>
<fragment pos="5"/>
</fragments>
</doc>
</root>
I played around with generate-key() a little bit, but could
not make it.
Can you help.
Thanks in advance.
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