xsl-list
[Top] [All Lists]

Re: Restructure via grouping

2005-02-09 05:58:18
Tempore 13:48:37, die 02/09/2005 AD, hinc in xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Robert Soesemann <rsoesemann(_at_)sapient(_dot_)com>:

How can I do the following restructuring? Do I need to use grouping?

Inside and outside of my <doc> node there are <fragment> nodes. I want
to collect them all and place them insde a new <fragments> tag.


You could use grouping but it's not necessary.
I think this will do:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output indent="yes"/>

<xsl:template match="root">
        <xsl:copy>
                <doc>
                        <fragments>
                                <xsl:copy-of select=".//fragment"/>
                        </fragments>
                </doc>
        </xsl:copy>
</xsl:template>

</xsl:stylesheet>


regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
"Et ipsa scientia potestas est"  - Francis Bacon , Meditationes sacrae

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--



<Prev in Thread] Current Thread [Next in Thread>