This:
<xsl:variable name="show">
<xsl:value-of select = "$time != 60000" />
</xsl:variable>
is not a boolean variable, it is a result tree fragment. If you convert a
result tree fragment to a boolean, the result is always true.
The correct way to write a boolean variable is:
<xsl:variable name="show" select="$time != 60000" />
I simply have no idea why this verbose, inefficient, and often incorrect
style using <xsl:value-of> within <xsl:variable> has become so popular.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ken Goodridge [mailto:goodridgehunting(_at_)yahoo(_dot_)com]
Sent: 08 February 2005 15:39
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Can I use a boolean variable in an xsl:if test
I've been using the following xsl with success, but
I am seeing the xsl:if not work properly in another
installation. In both cases I get
<debug><show>false</show><time>60000</time></debug>,
but in one case the noshow shows. Does this code break
the rules or am I seeing a bug in the xsl transform?
In both cases I'm using xalan. I can check to see if
the versions are different if someone thinks that may
help.
<xsl:template name="my_template">
<xsl:param name="time"/>
<!-- Don't show if time is one minute -->
<xsl:variable name="show">
<xsl:value-of select = "$time != 60000" />
</xsl:variable>
<debug>
<show><xsl:value-of select = "$show" /></show>
<time><xsl:value-of select = "$time" /></time>
</debug>
<xsl:if test="$show">
<noshow><xsl:value-of select = "$show" /></noshow>
</xsl:if>
</xsl:template>
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