sorry was some mising elements in the priviouse message :
hi
from the following xml database i am trying to output elements in revers
order :
<car>
<AA><x>40</x><y>360</y><AA>
<BB><x>40</x><y>360</y><x>120</x><y>280</y><BB>
<C> <x>120</x><y>280</y></C>
<D><x>40</x><y>360</y><x>120</x><y>280</y></D>
<E><x>10</x><y>3</y></E>
</car>
i used the following template xslt1.0:
<xsl:template match="car">
<xsl:copy>
<xsl:for-each select="*">
<xsl:sort select="position()" data-type="number"
order="descending" />
<xsl:copy>
<xsl:for-each select="x">
<xsl:sort select="position()" data-type="number"
order="descending" />
<xsl:copy-of select=". | following-sibling::y[1]" />
</xsl:for-each>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
then the result was as following :
<car>
<E><x>10</x><y>3</y></E>
<D><x>120</x><y>280</y> <x>40</x><y>360</y></D>
<C><x>120</x><y>280</y> </C>
<BB><x>120</x><y>280</y> <x>40</x><y>360</y><BB>
<AA><x>40</x><y>360</y><AA>
</car>
that is exactly was i wanted except that i want the elements (A,B,C,D,E)
to be in its original place such the following :
<car>
<AA><x>10</x><y>3</y><AA>
<BB><x>120</x><y>280</y> <x>40</x><y>360</y><BB>
<C><x>120</x><y>280</y> </C>
<D><x>120</x><y>280</y> <x>40</x><y>360</y></D>
<E><x>40</x><y>360</y> </E>
</car>
thanks
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