Unforturnately, stuck with single XPATH queries... so, here is what I
have come up with... I feel like I am really really close:
/data/animals/animal[(_at_)id = /data/code/record[field[(_at_)id = ( '60' )
]]/@id]
The above '60' is in correct context of /data/animals/animal (it is
the value of id).. do I lose context on the right hand side of this
equation? The following substition for '60' does not work
preceding-sibling::animal[1]/@id... so:
/data/animals/animal[(_at_)id = /data/code/record[field[(_at_)id = (
preceding-sibling::animal[1]/@id ) ]]/@id]
On Tue, 08 Mar 2005 22:19:56 +0100, Joris Gillis <roac(_at_)pandora(_dot_)be>
wrote:
Tempore 21:58:03, die 03/08/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Karl Stubsjoen
<kstubs(_at_)gmail(_dot_)com>:
<data>
<code>
<record id="40" says="ruff" animal="dog">
<field fieldname="chase" id="50">cat</field>
</record>
<record id="50" says="meow" animal="cat">
<field fieldname="chase" id="60">mouse</field>
</record>
<record id="60" says="squeak" animal="mouse">
<field fieldname="chase" id="00">cheese</field>
</record>
</code>
<animals>
<animal id="60" />
<animal id="50" />
<animal id="40" />
<animal id="50" />
<animal id="60" />
<animal id="40" />
<animal id="50" />
<animal id="40" />
<animal id="80" />
</animals>
</data>
I am interested in returning all matches for animals who are in a
proper "chase" order. So for example, the above animal who's ID is
50, is correctly in order if the proceding-animal is 40 (there should
be 2 matches). Similarily, the animal who's ID is 60 is in correct
order one time with the proceding-animal who's ID is 50. This "chase"
order is to be derived by the code/record lookup above.
Hi,
It would be easier to use keys here:
<xsl:key name="chases" match="field[(_at_)fieldname='chase']" use="../@id"/>
<xsl:template match="data">
<xsl:copy-of
select="animals/animal[(_at_)id=key('chases',preceding-sibling::animal[1]/@id)/@id]"/>
</xsl:template>
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
Spread the wiki (http://www.wikipedia.org)
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