The general rule with [xsl:]xxxx attributes is: use the xsl: prefix on the
attribute if it's not present on the element. So if the attribute is on the
xsl:stylesheet element, it should omit the prefix.
If it still doesn't work, it may because XML Spy hasn't yet implemented this
feature - I don't know. I would have expected that if the feature isn't
implemented, they would tell you.
Michael Kay
http://www.saxonica.com
-----Original Message-----
From: Jonathan Marenus [mailto:jonathanmarenus(_at_)yahoo(_dot_)com]
Sent: 04 March 2005 20:24
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Namespaces in XMLSpy
I am using XSLT version 2.0 and my stylesheet tag now
looks like this:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xsl:xpath-default-namespace="yyyy">
I haven't changed any other part of my code and I
tried the xpath-default-namespace with and without the
'xsl:'. I am still getting the same error I had
before. Any further ideas?
Jonathan Marenus
--- Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
Sorry the reply was so brief, it was late at night,
and I thought the
information might be enough.
Let's write expanded names in the form
{namespace}local.
In the document
<A xmlns="yyyy">
<B>
<C/>
</B>
</A>
you have three elements whose expanded names are
{yyyy}A, {yyyy}B, and
{yyyy}C.
In XSLT 1.0, to match an element {yyyy}A, you need
to bind a namespace
prefix to yyyy and use that prefix in the match
pattern or XPath expression
step. For example
<xsl:template match="y:A" xmlns:y="yyyy">
<xsl:value-of select="y:B/y:C"/>
</xsl:template>
In XSLT 2.0, you can set
xpath-default-namespace="yyyy" instead.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jonathan Marenus
[mailto:jonathanmarenus(_at_)yahoo(_dot_)com]
Sent: 04 March 2005 06:02
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Namespaces in XMLSpy
Ok, Let's say my XML file consists of 3 elements
A,B,C
with A being the outermost element with a
namespace
declaration of xmlns="yyyyy". In what way are the
element names B and C changed and in what way must
I
change the stylesheet to match those new names.
This
has been a problem at work that I have been
putting
off for the last 3 months and it has gotten to the
point where I must have it working. I just
started
using XSL 5 months ago so being explicit would
help
very much so.
Thanks.
Jonathan Marenus
--- Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
If you have a namespace declaration such as
xmlns="yyyyy" in your outermost
element, this changes the name of every element
in
your document, and your
stylesheet must be changed to match the new
names.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jonathan Marenus
[mailto:jonathanmarenus(_at_)yahoo(_dot_)com]
Sent: 03 March 2005 22:10
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Namespaces in XMLSpy
Ok, here's my problem:
I have both a namespace and a schema as
attributes in my root element. I am using
XMLSpy
to
transform the file, and for some unknown
reason,
it is
copying the entire original file into output
instead
of making the changes that I specify in the
XSL
file.
If I delete those attributes, the XSL
transformation
is successful, but I need to find a way for it
to
work
with the namespace and schema attributes in
there.
I
am not sure if this problem is specifically
related to
XMLSpy. It could be that I need to add
something
in
my XSL code or even a change in settings in
XMLSpy,
but either way, I need this resolved as soon
as
possible so any feedback would be greatly
appreciated.
Thanks.
Jonathan Marenus
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