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RE: xslt 2. Date arithmetic.

2005-03-01 09:24:03
The difference between two dates is a dayTimeDuration (if they're in the
same timezone - the usual case - then it will be an integer number of days).

Subtraction of dates to give a yearMonthDuration - the old
subtractDateTimesYieldingYearMonthDuration - has been removed (as befits any
function with such a ridiculous name) because it proved too difficult to
specify it. For example, would you expect 2005-02-28 minus 2005-01-31 to be
one month, on the basis that 2005-01-31 plus one month is 2005-02-28? But
surely the difference between these two dates is the same as 2004-02-28
minus 2004-01-31?

Depending what you actually want to achieve, the best approach is probably
to extract the year/month components (year-from-date(), month-from-date())
and manipulate the values yourself.

Michael Kay
http://www.saxonica.com/  

-----Original Message-----
From: Pawson, David [mailto:David(_dot_)Pawson(_at_)rnib(_dot_)org(_dot_)uk] 
Sent: 01 March 2005 15:51
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xslt 2. Date arithmetic.


<xsl:variable name="t1" 
   select="xs:date('2002-09-01')"/>
 <xsl:variable name="t2" select="current-date()" />

 <xsl:variable name="dur" 
   select="xdt:yearMonthDuration($t2 - $t1)"  
as="xdt:yearMonthDuration"
   />

 <xsl:sequence
 select="$dur" /> 


I'm getting casting errors, and I can't see a way of resolving it.
Error on line xx:
  FORG0001: Cannot convert to yearMonthDuration because some 
components are non-
zero
Transformation failed: Run-time errors were reported

yes.... agree they are non-zero. 



Any help appreciated.


Regards DaveP.

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