You can probably tell my inexperience with this because I probably opted to
take the most complex path possible. I will give this a try on Monday and
see what I can come up with.
Thanks again for the help,
Chris
-----Original Message-----
From: Wendell Piez [mailto:wapiez(_at_)mulberrytech(_dot_)com]
Sent: Friday, April 01, 2005 4:49 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Combining two node Sets into one
Chris,
At 04:24 PM 4/1/2005, you wrote:
I have no way now to get the dates in order without calling some
ridiculous recursive template that sorts the nodes for me and prints
the appropriate one. Loop.. Print. which could result in a high number
of passes..
Why not sort them with the same instruction you'd use to sort them if
converting them to an intermediate format?
<xsl:template match="/">
<table>
<xsl:apply-templates select="//Disbs | //Refunds">
<xsl:sort select="DisbDetail/Ddate | RefDetail/Rdate"/>
</xsl:apply-templates>
</table>
</xsl:template>
<xsl:template match="Disbs | Refund">
<tr class="{local-name()}">
... etc ...
</tr>
</xsl:template>
... the 'class' attribute there gets the value "Disbs" or "Refund" -- i.e.
the name of the matched element.
There are cases where complex sorting and grouping requirements push us
into having to process temporary trees, but I haven't yet seen anything
here that makes me think this is one of them.
Cheers,
Wendell
======================================================================
Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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Mulberry Technologies: A Consultancy Specializing in SGML and XML
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