RE: Combining two node Sets into one

I solved the problem by using..

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                xmlns:exsl="http://exslt.org/common";
                extension-element-prefixes="exsl"
                version="1.0">
  ...
  <!-- Now we can convert result tree fragment back to node-set -->
  <xsl:value-of select="exsl:node-set($author)/email"/>

But how does this effect the output for browsers such as mozilla, netscape,
and IE?  Will the browsers act differently?

-----Original Message-----
From: Wendell Piez [mailto:wapiez(_at_)mulberrytech(_dot_)com] 
Sent: Thursday, March 31, 2005 5:38 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Combining two node Sets into one


Chris,

At 03:27 PM 3/31/2005, you wrote:
> Is there any possible way to combine two node sets into one single node 
> set (assign to variable?) and then add an extra childnode to the set 
> based on which parent node the new node came from.
Sure, this is a fairly straightforward "plain vanilla" XML->XML 
transformation, maybe with a few sprinkles....

You'll need at some point to select all the Disbs and Refunds elements 
together -- that's where you'll do your sorting by date, and also where 
you'll create the wrapper for the entire output:

<xsl:template match="/">
   <Trans>
     <xsl:apply-templates select="//Disbs | //Refunds">
       <xsl:sort select="DisbDetail/Ddate | RefDetail/Rdate"/>
     </xsl:apply-templates>
   </Trans>

Now you need templates to match the Disbs and Refunds elements, and for 
their descendants in turn (which will map to your new elements). I'll just 
show you a couple of them:

<xsl:template match="Disbs">
   <xsl:apply-templates/>
   <!-- nothing to be done here except select and process our
        children, which will map -->
</xsl:template>

<xsl:template match="DisbDetail">
   <!-- maps to TranDetail -->
   <TranDetail>
     <!-- but here we need to announce our type: -->
     <Ttype>dis</Ttype>
     <xsl:apply-templates/>
   <!-- descends another level -->
   </TranDetail>
</xsl:template>

<xsl:template match="Damount">
   <Tamount>
     <xsl:apply-templates/>
   </Tamount>
</xsl:template>

and so forth.

Once you've got all these templates, you'll find many of them are very 
similar ... for example you'll have

<xsl:template match="RefDetail">
   <!-- maps to TranDetail, and descends another level -->
   <TranDetail>
     <!-- but here we need to announce our type: -->
     <Ttype>refund</Ttype>
     <xsl:apply-templates/>
   </TranDetail>
</xsl:template>

... notice this is almost exactly like the template matching DisbDetail. 
(The one matching Ramount will be exactly like the one matching Damount.)

So they can be combined:

<xsl:template match="DisbDetail | RefDetail">
   <!-- maps to TranDetail, and descends another level -->
   <TranDetail>
     <!-- but here we need to announce our type: -->
     <Ttype>
       <xsl:choose>
         <xsl:when test="self::DisbDetail">dis</xsl:when>
         <xsl:otherwise>refund</xsl:otherwise>
       </xsl:choose>
     </Ttype>
     <xsl:apply-templates/>
   </TranDetail>
</xsl:template>

Your entire stylesheet will have just a few fairly simple templates.

I hope that helps! If anything here is mysterious to a newbie, my guess 
it'll be about how templates match and how xsl:apply-templates works ... 
the famous XSLT processing model.

Cheers,
Wendell


======================================================================
Wendell Piez                            
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
   Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================


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