Gowtham,
stylesheet will extract only some information (filter) from the XML and
create a table. I want the rows in this table to have alternate background
color. Because of the filter condition in the XSL, I cannot use the
position() to check for odd/even rows. I need to (essentially) check the
row number inserted into the HTML <TABLE>.
Here're 2 XSLT 1.0 options: split the transform into 2 stylesheets--the
first picks out only the rows you want, and the second formats them into
HTML, this time using position() to determine even/odd rows. Alternatively
you could do this in 1 stylesheet if you're willingto use an extension
function such as node-set(). The idea here is to create a variable
containing the rows you want, then to iterate rows inthis variable, this
time using position(). Something like so:
My mistake in the response (above). position() keeps in step with the
position of a node wrt its position in a [selected] nodeset, not just its
position in the original document. It's properties such as prior-sibling,
etc, that don't change from their original values. The upshot being that
you don't need node-set() for what you're trying to do.
The following XSL picks out just the nodes of interest, adding a 0/1
according as the picked-out node is even/odd in the new nodeset. The
(position() - 1) business is just to translate position() to be 0-based.
Just to verify, you may want to change the selection below to nodes that you
know are even/odd in the input XML, and still see that they take on 0/1
attributes based on their position in the newly-selected nodeset.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output indent="yes"/>
<xsl:template match="/">
<table>
<xsl:apply-templates select="/Codes/Code[Name = 30 or Name=50 or
Name=60]"/>
</table>
</xsl:template>
<xsl:template match="Code">
<xsl:copy>
<xsl:attribute name="color">
<xsl:value-of select="(position() - 1) mod 2"/>
</xsl:attribute>
<xsl:copy-of select="*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
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