stylesheet will extract only some information (filter) from the XML and
create a table. I want the rows in this table to have alternate background
color. Because of the filter condition in the XSL, I cannot use the
position() to check for odd/even rows. I need to (essentially) check the
row number inserted into the HTML <TABLE>.
Here're 2 XSLT 1.0 options: split the transform into 2 stylesheets--the
first picks out only the rows you want, and the second formats them into
HTML, this time using position() to determine even/odd rows. Alternatively
you could do this in 1 stylesheet if you're willingto use an extension
function such as node-set(). The idea here is to create a variable
containing the rows you want, then to iterate rows inthis variable, this
time using position(). Something like so:
<xsl:variable name="r">
<xsl:copy-of select="Codes/Code[Name = 30 ... etc]"/>
</xsl:variable>
<xsl:for-each select="node-set($r)">
//.. do something with .
</xsl:for-each>
node-set comes into play because what's held in $r is a "result tree
fragment", which needs to be converted to a "nodeset" before it may be
iterated over, etc.
I gather that XSLT 2.0 has features that obviate this step.
Regards,
--A
<Codes>
<Code>
<Name>10</Name>
<Description>Decription 10</Description>
</Code>
<Code>
<Name>20</Name>
<Description> Description 20</Description>
</Code>
<Code>
<Name>30</Name>
<Description>description 30</Description>
</Code>
<Code>
<Name>40</Name>
<Description> Description 40</Description>
</Code>
</Codes>
And here is my stylesheet (it extracts only codes 30, 50 & 60). The output
should contain the first and third rows in one bg color and the second row
in a different color. I tried the position() in this XSL, but it does not
work...
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