<xsl:for-each select="*">
<xsl:value-of select="name()" />
<xsl:for-each select="@*">
<xsl:value-of select="current()" />
The current() function returns the node matched by the template.
Try
<xsl:value-of select="." />
instead.
J.Pietschmann
Not so. As a self-contained XPath expression, current() returns exactly the
same as ".". It's only inside a predicate that the result is different.
Michael Kay
http://www.saxonica.com/
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