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Re: multiple node values not being returned

2005-05-20 04:57:08


David Carlisle wrote:

Is there a one line code available to do the same thing?

No, why should there be? You can copy all the nodes using copy-of but if
you want to generate a new element and new text then you need to iterate
over the old nodes and generate some new ones.

Ive finally solved my problem and am now getting the results I expected. Heres what I did

<xsl:for-each select="$interim/A/Value">
          <xsl:variable name="aVal" select="."/>
<xsl:value-of select="distinct-values($aVal[for $a in . return $oVal[contains(.,$a)]])"/> <xsl:if test="position() != last()"><xsl:value-of select="' '"/></xsl:if> </xsl:for-each> Thank you so much for helping out. On hindsight it was a fairly straight-forward solution. Probably my head was playing games!

Thanks a lot once again
Rahil

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