RE: select a node: child of an ancestor

Anthony, just your luck there've been at least 3 posts today about just this 
business of determining some property of a "related" node.
So, this XML (yours, extended):

<data>
<LeftNavTree n="1">
 <LeftNavParamList>
   <SelectedNode>Link 1.1.1</SelectedNode>
 </LeftNavParamList>
 <TreeNodeList>
   <TreeNode>
     <NodeID>Link 1</NodeID>
     <NodeContent>...</NodeContent>
     <TreeNodeList>
       <TreeNode>
         <NodeID>Link 1.1</NodeID>
         <NodeContent>...</NodeContent>
         <TreeNodeList>
         <TreeNode>
           <NodeID>Link 1.1.1</NodeID>
           <NodeContent>...</NodeContent>
         </TreeNode>
     </TreeNodeList>
   </TreeNode>
  </TreeNodeList>
 </TreeNode>
</TreeNodeList>
</LeftNavTree>

<LeftNavTree n="2">
 <LeftNavParamList>
   <SelectedNode>Link 2.2.2</SelectedNode>
 </LeftNavParamList>
 <TreeNodeList>
   <TreeNode>
     <NodeID>Link 2</NodeID>
     <NodeContent>...</NodeContent>
   </TreeNode>
  </TreeNodeList>
</LeftNavTree>
</data>

With this XSL:

<?xml version="1.0" encoding="iso8859-1"?>
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
   <xsl:output method="xml" indent="yes"/>

   <xsl:template match="/">
       <data>
       <xsl:apply-templates select="//NodeID"/>
       </data>
   </xsl:template>

   <xsl:template match="NodeID">
       <xsl:copy>
           <xsl:attribute name="SelectedNode">
               <xsl:value-of 
select="ancestor::LeftNavTree//SelectedNode[1]"/>
           </xsl:attribute>
           <xsl:value-of select="."/>
       </xsl:copy>
   </xsl:template>

</xsl:stylesheet>


Yields this:

<?xml version="1.0" encoding="UTF-8"?>
<data>
 <NodeID SelectedNode="Link 1.1.1">Link 1</NodeID>
 <NodeID SelectedNode="Link 1.1.1">Link 1.1</NodeID>
 <NodeID SelectedNode="Link 1.1.1">Link 1.1.1</NodeID>
 <NodeID SelectedNode="Link 2.2.2">Link 2</NodeID>
</data>

Of course, you could optimize this quite a few ways, but you get the idea.

Regards,

--A

> From: Anthony <apwebdesign(_at_)yahoo(_dot_)com>
> Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> Subject: [xsl] select a node: child of an ancestor
> Date: Thu, 19 May 2005 16:55:51 -0700 (PDT)
>
> I have the following xml tree, in which I need to
> compare the value of <SelectedNode> with <NodeId>
> while iterating:
>
>
> <LeftNavTree>
>   <LeftNavParamList>
>     <SelectedNode>Link 1.1.1<</SelectedNode>
>   </LeftNavParamList>
>   <TreeNodeList>
>     <TreeNode>
>       <NodeID>Link 1</NodeID>
>       <NodeContent>...</NodeContent>
>       <TreeNodeList>
>         <TreeNode>
>           <NodeID>Link 1.1</NodeID>
>           <NodeContent>...</NodeContent>
>           <TreeNodeList>
>           <TreeNode>
>             <NodeID>Link 1.1.1</NodeID>
>             <NodeContent>...</NodeContent>
>           </TreeNode>
>       </TreeNodeList>
>     </TreeNode>
>    </TreeNodeList>
>   </TreeNode>
> </TreeNodeList>
> </LeftNavTree>
>
> There could be more than one LeftNavTree, so
> originally I was using this xpath:
> //p:LeftNavTree/p:LeftNavParamList/p:SelectedNode
>
> But it's concatonating the values of SelectedNode from
> both LeftNavTree's. I need an xpath expression that
> will grab "the SelectedNode element which is a
> descendent of the ancestor LeftNavTree element for the
> current node".
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