Hi,
Here's another variation.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="br">
<xsl:text>
</xsl:text>
</xsl:template>
<xsl:template match="text()[not(normalize-space(.) = '')]">
<line>
<xsl:value-of select="normalize-space(.)"/>
</line>
</xsl:template>
</xsl:stylesheet>
Cheers,
Omprakash.V
"Aron Bock"
<aronbock(_at_)hot To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
mail.com> cc: (bcc: omprakash.v/Polaris)
Subject: RE: [xsl] XPath query
syntax
05/19/2005
04:54 AM
Please
respond to
xsl-list
Jon, some variant of this should work. You may also want to use
normalize-space().
<?xml version="1.0" encoding="iso8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml"/>
<xsl:template match="/">
<xsl:for-each select="/textarea/node()[name() != 'br']">
<line><xsl:copy-of select="."/></line>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
From: jpk <jopaki(_at_)yahoo(_dot_)com>
I have source XML:
<textarea>
line 1<br/>
line 2<br/>
line 3<br/>
line 4<br/>
</textarea>
How do I query for each of the line texts? That is, I
need to get each text [node] that preceeds all <br>
tags.
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