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RE: XPath query syntax

2005-05-18 16:24:37
Jon, some variant of this should work. You may also want to use normalize-space().

<?xml version="1.0" encoding="iso8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
   <xsl:output method="xml"/>

   <xsl:template match="/">
       <xsl:for-each select="/textarea/node()[name() != 'br']">
           <line><xsl:copy-of select="."/></line>
       </xsl:for-each>
        </xsl:template>

</xsl:stylesheet>


From: jpk <jopaki(_at_)yahoo(_dot_)com>
I have source XML:

<textarea>
  line 1<br/>
  line 2<br/>
  line 3<br/>
  line 4<br/>
</textarea>

How do I query for each of the line texts?  That is, I
need to get each text [node] that preceeds all <br>
tags.

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