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Re: flat XML to normal XML

2005-05-16 07:06:56





Hi,
     With just the first node commented thus not providing support for
handling the transport tag, the following stylesheet produces the output
you want.
Iam sure this can be extended to handle the transpot tags.

Cheers,
Omprakash.V

XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>


 <xsl:template match="/">
  <NewNodeSet>
   <xsl:apply-templates select="/DataSet/Table[1]">
      <xsl:with-param name="level" select="/DataSet/Table/Level"/>
      </xsl:apply-templates>

  </NewNodeSet>
 </xsl:template>

<xsl:template match="Table">
<xsl:param name="level"/>


<Brand name="{Description}">
      <xsl:apply-templates select="following::Table[1]" mode="model">
      <xsl:with-param name="level" select="$level"/>
      </xsl:apply-templates>
</Brand>

      <xsl:apply-templates select="following::Table[Level =
number($level)]">
      <xsl:with-param name="level" select="$level"/>
      </xsl:apply-templates>

</xsl:template>

<xsl:template match="Table" mode="model">
<xsl:param name="level"/>


<xsl:if test="not(Level = number($level))">

<Model>
      <xsl:value-of select="Description"/>
</Model>
      <xsl:apply-templates select="following::Table[1]" mode="model">
      <xsl:with-param name="level" select="$level"/>
      </xsl:apply-templates>
</xsl:if>

</xsl:template>



</xsl:stylesheet>

XML File:

<?xml version="1.0" encoding="UTF-8"?>
<DataSet xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>

<!--
      <Table>
        <Level>1</Level>
        <Description>Cars</Description>
    </Table>
-->
    <Table>
        <Level>2</Level>
        <Description>BMW</Description>
    </Table>

      <Table>
        <Level>3</Level>
        <Description>316</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>Z4</Description>
    </Table>
    <Table>
        <Level>2</Level>
        <Description>Citroen</Description>
    </Table>

      <Table>
        <Level>3</Level>
        <Description>C2</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>C4 coupe</Description>
    </Table>
    <Table>
        <Level>2</Level>
        <Description>Alfa Romeo</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>156</Description>
    </Table>


    <Table>
        <Level>1</Level>
        <Description>Motorcycles</Description>
    </Table>

    ...
    ...
</DataSet>


Output:

<?xml version="1.0" encoding="UTF-8"?>
<NewNodeSet>
<Brand name="BMW">
<Model>316</Model>
<Model>Z4</Model>
</Brand>
<Brand name="Citroen">
<Model>C2</Model>
<Model>C4 coupe</Model>
</Brand>
<Brand name="Alfa Romeo">
<Model>156</Model>
<Model>Motorcycles</Model>
</Brand>
<Brand name="Alfa Romeo">
<Model>156</Model>
<Model>Motorcycles</Model>
</Brand>
</NewNodeSet>






                                                                                
                                                      
                      Borut Bolčina                                             
                                                      
                      <bob(_at_)najdi(_dot_)si>           To:      
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com                                
               
                                               cc:      (bcc: 
omprakash.v/Polaris)                                                    
                      05/16/2005 03:54         Subject: [xsl] flat XML to 
normal XML                                                  
                      PM                                                        
                                                      
                      Please respond                                            
                                                      
                      to xsl-list                                               
                                                      
                                                                                
                                                      
                                                                                
                                                      




Hello list,

I wish to transform an xml which has level information in each item
(Table) to xml which has hierarchy as stated in those item's element.

<DataSet xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>
    <Table>
        <Level>1</Level>
        <Description>Cars</Description>
    </Table>
    <Table>
        <Level>2</Level>
        <Description>BMW</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>316</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>Z4</Description>
    </Table>
    <Table>
        <Level>2</Level>
        <Description>Citroen</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>C2</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>C4 coupe</Description>
    </Table>
    <Table>
        <Level>2</Level>
        <Description>Alfa Romeo</Description>
    </Table>
    <Table>
        <Level>3</Level>
        <Description>156</Description>
    </Table>
    <Table>
        <Level>1</Level>
        <Description>Motorcycles</Description>
    </Table>
    ...
    ...
</DataSet>


Target xml should look something like this:

<NewDataSet>
    <Transport name="Cars">
       <Brand name="BMW">
          <Model>316</Model>
          <Model>Z4</Model>
       </Brand>
       <Brand name="Citroen">
          <Model>C2</Model>
          <Model>C4 coupe</Model>
       </Brand>
       <Brand name="Alfa Romeo">
          <Model>156</Model>
       </Brand>
    </Transport>
    <Transport name="Motorcycle">
       ...
    </Transport>
</NewDataSet>


So, based on the Level element in the source xml for each Table entry,
an appropriate subtree must be constructed and inserted in target xml.
Levels are ordered following this pattern:
1,2,3,3,...,3,2,3,...,3,...,1,2,3,3,...,2,3,...,3

Busting my head over this for two days now, help appreciated. If only I
could find the guy who created this "flat" xml...$%##@@!

--Bob


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