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RE: <xsl:sort>

2005-05-07 15:26:24
Thank you all for your helpful replies.

In case anyone is interested I addressed the issue as follows.

<xsl:for-each select="child::node()">
  <xsl:if test="position() > 2 and local-name() != 'product'">
    <xsl:apply-templates select="." />
  </xsl:if>
</xsl:for-each>
<xsl:apply-templates select="product">
  <xsl:sort select="category" data-type="number" order="descending" />
</xsl:apply-templates>


Respectfully,

ASP


-----Original Message-----
From: Aron Bock [mailto:aronbock(_at_)hotmail(_dot_)com]
Sent: Saturday, May 07, 2005 5:43 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] <xsl:sort>


You could use something a prior respondent posted:

Incidentally this could be rewritten

<xsl:template match="document">
  ...
  <xsl:apply-templates select="child::node()[position() > 2]"/>
  <xsl:apply-templates select="child::product">
    <xsl:sort.../>
  </xsl:apply-templates>
</xsl:template>

Michael Kay

Enhancing it with:

<xsl:template match="document/*[not(product)]">
/template

<xsl:template match="product[position()=1]">
/template

<xsl:template match="product[position() > 1]">
/template


etc.

The idea is that one or more "main" templates select nodes ... which are
processed by other specifically-matching templates.

Some of these secondary templates, say, the non-product-matching ones which
need to handle varying preamble, could be put into a separate stylesheet,
and imported into this one via <xsl:import/>.

Archives of this ng also show how to apply templates based on a
dynamically-determined criterion.

That said, in my limited experience the advisability of using a single
stylesheet to transform markedly different content is suspect.

Regards,

--A

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