Thanks for the reply, George.
I gave your suggestion a try, but it still does not affect the sort order of
<product> elements. In the resultant document, they continue to appear in
the orginal XML document order.
Respectfully,
ASP
-----Original Message-----
From: George Cristian Bina [mailto:george(_at_)sync(_dot_)ro]
Sent: Saturday, May 07, 2005 4:13 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] <xsl:sort>
Hi,
You select only one node (the current node that is a product element)
and apply templates on it sorting this set (of one node) according with
your criteria.
Something like below may behave as you expect:
<xsl:template match="document">
<xsl:for-each select="child::node()">
<!-- whatever processing you want to do -->
</xsl:for-each>
<xsl:apply-templates select="product">
<xsl:sort select="category" data-type="number" order="descending"/>
</xsl:apply-templates>
</xsl:template>
Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com
aspsa wrote:
Hi, folks.
I have an XML document which structure is the following:
<document>
<header>
<paragraph>
<subheader>
<paragraph>
.
.
.
<product>
<partname>
<category>
.
.
.
</product>
<product>
<partname>
<category>
.
.
.
</product>
.
.
.
</document>
In a template that matches on "document", I have the following:
<xsl:template match="document">
<xsl:for-each select="child::node()">
// etc...
</xsl:for-each>
</xsl:template>
The XSLT stylesheet works fine, but now I need to sort the "product"
elements based upon the "category" element and in descending order. The
category content is numeric.
How would I execute this from within the "document" template?
Here's what I've tried.
<xsl:template match="document">
<xsl:for-each select="child::node()">
<xsl:if test="product">
<xsl:apply-templates select=".">
<xsl:sort select="category" data-type="number" order="descending"
/>
</xsl:apply-templates>
</xsl:if>
</xsl:for-each>
</xsl:template>
Where am I going wrong? Thanks for your feedback.
Respectfully,
ASP
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