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Re: Newbie question on Recusrion using XLST 1.0 Part 2

2005-05-01 20:47:16


Hi,

        If you'd like the template  to be called based on some condition,
then the call to the template should occur inside the region where the
condition evaluates to true. I have modified your code to demonstrate this
below:

                     <xsl:choose>
                       <xsl:when
test="$employeeList/employees/employee[position() &gt; 1]"/>
                       <!--Get the remaining employee EID attributes -->
                       <xsl:call-template name="DisplayEmployees">
                               <xsl:with-param name="employeeList"
select="$employeeList[position() &gt; 1]"/>
                       </xsl:call-template>
<!-- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ Note I have moved the
call-template inside the xsl:choose  -->
                       </xsl:choose>



Though in you case, there doesn't appear to be any need to perform this
check. Also, the above comment on your code doesn't mean that Iam
recommending this approach.

Cheers,
Omprakash.V








                                                                                
                                    
                    "Marco                                                      
                                    
                    Mastrocinque"         To:     
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>                              
   
                    <mmfive(_at_)netspa        cc:     (bcc: 
omprakash.v/Polaris)                                        
                    ce.net.au>            Subject:     [xsl] Newbie question on 
Recusrion using XLST 1.0 Part 2     
                                                                                
                                    
                    05/02/2005                                                  
                                    
                    06:51 AM                                                    
                                    
                    Please respond                                              
                                    
                    to xsl-list                                                 
                                    
                                                                                
                                    
                                                                                
                                    




Hi All,
       Following from my previous email. I have updated my code to no
avail.
Again I won't to display each EID attribute for each employee grouped by
division, using XSLT version 1.0.

Any suggestions most appreciated.

Thanks Marco Mastrocinque


<xsl:variable name="result">
   <xsl:call-template name="DisplayEmployees">
           <xsl:with-param name="employeeList" select="company/division"/>
   </xsl:call-template>
</xsl:variable>

<br/>
<h3>The value of result is <xsl:value-of select="$result"/></h3>


</xsl:template>
    <xsl:template name="DisplayEmployees">
    <!--This is a recursive routine-->
    <xsl:param name="employeeList"/>
            <xsl:choose>
               <xsl:when test="not($employeeList)">
               <!--If the nodelist is empty return true-->
                      <xsl:text>true</xsl:text>
               </xsl:when>
               <xsl:otherwise>
                     <xsl:choose>
                     <!--Get the first employee EID attribute -->
                     <xsl:when test="$employeeList/employees/employee[1]">
                       <xsl:value-of select="@EID"/>
                     </xsl:when>
                     <xsl:otherwise>
                     <!--Get the remaianing EID attributes -->
                     <xsl:choose>
                       <xsl:when
test="$employeeList/employees/employee[position() &gt; 1]"/>
                       </xsl:choose>
                       <!--Get the remaining employee EID attributes -->
                       <xsl:call-template name="DisplayEmployees">
                               <xsl:with-param name="employeeList"
select="$employeeList[position() &gt; 1]"/>
                       </xsl:call-template>
                </xsl:otherwise>
             </xsl:choose>
            </xsl:otherwise>
      </xsl:choose>
    </xsl:template>
</xsl:stylesheet>


-----Original Message-----
From: Marco Mastrocinque [mailto:mmfive(_at_)netspace(_dot_)net(_dot_)au]
Sent: Saturday, 30 April 2005 5:16 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Newbie question on Recusrion using XLST 1.0

Hi All,
       I have an example file with the following structure:

<company>
   <division DID="Sal">
      <employees>
                     <employee EID="EMP001">
                        <ENAME>Joe Blow</ENAME>
               <OFFICE>1.2.27</OFFICE>
               <BIRTHDATE>1963-08-01</BIRTHDATE>
                        <SALARY>28790</SALARY>
                     </employee>
                     <employee EID="EMP002">
                        <ENAME>John Doe</ENAME>
               <OFFICE>1.2.2</OFFICE>
               <BIRTHDATE>1970-08-01</BIRTHDATE>
                        <SALARY>29855</SALARY>
                     </employee>
           </employees>
   </division>
   <division DID="SOF">
      <employees>
                     <employee EID="EMM001">
                        <ENAME>Mark Smith</ENAME>
               <OFFICE>1.2.27</OFFICE>
               <BIRTHDATE>1966-08-01</BIRTHDATE>
                        <SALARY>35000</SALARY>
                     </employee>
                     <employee EID="EMM002">
                        <ENAME>John Doe</ENAME>
               <OFFICE>1.2.2</OFFICE>
               <BIRTHDATE>1977-08-01</BIRTHDATE>
                        <SALARY>40000</SALARY>
                     </employee>
           </employees>
   </division>
</company>



I'm having using a recursive routine (see below) to display the following
elements and attributes:
1) The employee EID attribute such as 'EMP001', followed by
2) The element text of ENAME, such as 'Joe Blow',
3) The element text of OFFICE, such as '1.2.27'
4) The output must be formatted such that the employees of each division
are
grouped together.

Here is my code so far, for the above snippet of XML code which has
numerous
errors:

<xsl:variable name="result">
  <xsl:call-template name="DisplayEmployees">
           <xsl:with-param name="employeeList" select="company/division"/>
  </xsl:call-template>
</xsl:variable>
<xsl:value-of select="$result"/>


<xsl:template name="DisplayEmployees">
    <!--This is a recursive routine-->
                     <xsl:param name="employeeList"/>
                     <xsl:choose>
                               <xsl:when test="not($employeeList)">
                                   <!--If the nodelist is empty return
true-->
                                          <xsl:text>true</xsl:text>
                               </xsl:when>
                               <xsl:otherwise>
                                          <xsl:choose>
                                                    <xsl:when
test="employees/employee[(_at_)EID]">
                                                              <xsl:value-of
select="@EID"/>
                                                    </xsl:when>
                                          </xsl:choose>
                               </xsl:otherwise>
                     </xsl:choose>
    </xsl:template>

I can't seem to get any output. Trying to put it in a html file. Please
note
I'm new to XSLT and XPATH so please excuse the numerous errors.

Thanks Marco Mastrocinque


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