Hi Roman,
I thought the following stylesheet would have
worked.. But its not working. Its identity template
based ..
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes" />
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="exp">
<xsl:if test="not(name(preceding-sibling::*[1]) =
'exp')">
<remark>
<xsl:copy-of select=". | following-sibling::exp"
/>
</remark>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- Huditsch Roman <Roman(_dot_)Huditsch(_at_)lexisnexis(_dot_)at>
wrote:
Good morning list,
I would like to group adjacent siblings which share
the same local-name
into a container element.
Given this structure
<ax>
<e></e>
<r></r>
<exp>Example</exp>
<exp>bla bla</exp>
<exp>jada jada</exp>
<b></b>
<e></e>
<exp>Example 2</exp>
<exp>bla bla</exp>
<v></v>
</ax>
<bx>
<c></c>
<exp>Example 3</exp>
<exp>bla bla</exp>
<b></b>
</bx>
The following output should be produced:
<ax>
<e></e>
<r></r>
<remark>
<exp>Example</exp>
<exp>bla bla</exp>
<exp>jada jada</exp>
</remark>
<b></b>
<e></e>
<remark>
<exp>Example 2</exp>
<exp>bla bla</exp>
</remark>
<v></v>
</ax>
<bx>
<c></c>
<r></r>
<remark>
<exp>Example 3</exp>
<exp>bla bla</exp>
</remark>
<b></b>
</bx>
I thought that this would be the classical use-case
for an
<xsl:for-each-group> with @group-adjacent, but I am
getting the
strangest results...
I don't even know if it is better to do the grouping
in a template
matching
exp[not(preceding-sibling::*[1][local-name()='exp'])
or in a template
matching exp's parent
I also tried to find a @group-starting-with
solution, since the first
<exp> always starts with the string 'Example'. But
with no success
either....
Can you help me with this problem?
Thank you very much for your help!
Wbr,
Roman
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