Billie,
At 01:29 PM 6/24/2005, you wrote:
I gave the diagrams the appropriate names so you could see what I was
looking for, but basically,
I'm looking for a way to number the diagrams based on the absolute order
in which they are placed.
This statement of the problem suggests it might be handled with the
xsl:number instruction, which is designed to do this.
You might want <xsl:number level="any"/>. A good XSLT reference will help.
I've tried all sorts of combinations but nothing seemed to work. One
logical structure I came up
with, that I couldn't figure out how to translate into XSL, was: "count
the number of diagrams that
have an ancestor-or-self which is a preceding-sibling to an
ancestor-or-self of the diagram in
question". Is that possible to do?
Yes (sort of), but there are also easier ways, such as using
"count(preceding::diagram)". You don't need to worry about counting
ancestors unless diagrams are allowed to contain other diagrams.
But xsl:number is the thing to use unless there's some reason not to.
Cheers,
Wendell
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Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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Mulberry Technologies: A Consultancy Specializing in SGML and XML
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