Hi Billie,
Probably the following code might help ..
<xsl:template match="diagram">
<xsl:attribute name="Number">
<xsl:value-of select="count(preceding::node()
| ancestor::node())"/>
</xsl:attribute>
</xsl:template>
This is not tested.
(I am relying on this technique based on a problem I
solved earlier.)
Regards,
Mukul
--- Billie <whynot77(_at_)coolgoose(_dot_)com> wrote:
I need help with a problem I'm having. I need to
count the number of nodes that come before the
given node, anywhere in the tree.
So for example, say I have this tree:
<book>
<chapter>
<para>
Blah blah blah
<diagram name="first"/>
</para>
<para>Blah blah blah</para>
<para>
<diagram name="second"/>
Blah blah blah
</para>
<diagram name="third"/>
</chapter>
<chapter>
<para>Blah blah blah</para>
</chapter>
<chapter>
<diagram name="fourth"/>
<para>Blah blah blah</para>
</chapter>
<chapter>
<para>
<quote>
<diagram name="fifth"/>
<diagram name="sixth"/>
Blah blah blah
</quote>
</para>
</chapter>
</book>
I gave the diagrams the appropriate names so you
could see what I was looking for, but basically,
I'm looking for a way to number the diagrams based
on the absolute order in which they are placed.
I've tried all sorts of combinations but nothing
seemed to work. One logical structure I came up
with, that I couldn't figure out how to translate
into XSL, was: "count the number of diagrams that
have an ancestor-or-self which is a
preceding-sibling to an ancestor-or-self of the
diagram in
question". Is that possible to do?
<xsl:template match="diagram">
<xsl:attribute name="Number">
<xsl:value-of select="???"/>
</xsl:attribute>
</xsl:template>
Thanks for your help,
Billie
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