On Jun 22, 2005, at 1:10 AM, xsl-list-digest-
help(_at_)lists(_dot_)mulberrytech(_dot_)com wrote:
Date: Tue, 21 Jun 2005 23:24:29 +0100
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Subject: Re: [xsl] Contexts that are atomic values
Message-Id:
<200506212224(_dot_)XAA23479(_at_)penguin(_dot_)nag(_dot_)co(_dot_)uk>
Is this behavior normal?
Yes, or at least it will be. (It's best to say if you are using
xslt2:-)
distinct-values() as its name suggests returns values not teh nodes
the
values they were in, so it's like going
<xsl:for-each select="(1,2,3,4)"
in which the current item would be the integers 1 2 3 4 but being
integers rather than nodes they can't be used as the base for any
relative XPath (or even / as that depends on the current dpcument)
That there's no current node while processing a scalar value, I
understand, but why can't there be a current document?
you can go
<xsl:variable name="input" select="/"/>
as a top level variable (or anywhere outside the for-each)
and then use
<xsl:apply-templates
select="$input/key('by-type',current())"/>
or equivalently
<xsl:apply-templates
select="key('by-type',current(),$input)"/>
Or perhaps more naturally don't use distinct-values at all, but
ciew it
as a grouping problem
<xsl:for-each-group select="item" group-by="@type">
...
for-each-group groups the nodes themselves rather than just the
values.
I don't know why I didn't think of using a variable. As for 'for-
each-group', I didn't know it existed at all :-) Of, course, the for-
each-group approach is the best solution (once you figure out there's
also a current-group() function, which is not obvious from the w3.org
documentation...).
Thanks a lot for your help,
MC
--
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