I'm sorry, I am lost ;-)
Let's take an example XML and XSLT:
XML:
<example>
<types xmlns:aa="www.super.org/aa" xmlns:bb="www.super.org/bb">
<type name="aa:foo"/>
<type name="bb:foo"/>
</types>
<xx xmlns:foo="www.super.org/bb" type="foo:bar"/>
<example>
XSLT:
<xsl:templare match="xx">
<!-- this will NOT select what I really mean - the
//type[(_at_)name="bb:foo"] element -->
<xsl:copy-of select="//type[(_at_)name=current()/@type]"/>
</xsl:templare">
How can I select in the copy-of the right type, if the value in the
argument is a qname?
tomi
-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: Tuesday, June 07, 2005 2:17 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Creating namespace nodes
we must strip away the namespace
prefix, as accomplished by the substring-after() function.
yes in xslt attribute values are just strings so you need to use
substring, although you have access to all in scope namespace so you can
do this in a namespace correct fasion, you don't ever need to assume any
fixed prefixes.
XSLT2 with a schema aware processor would know that these attributes
were types as qnames so then you woul dbe able to use local-name() and
similar functions rather than string handling functions to access the
local name and namespace URI.
David
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