This should work.
<xsl:for-each
select="//ApplicationData/Revision_Record[./RevisionLetter!='NEW']">
<xsl:sort select="./RevisionLetter" order="ascending"/>
<xsl:if test="position()=last()">
<xsl:call-template name="RevisionRecord">
<xsl:with-param name="this-rev-letter"
select="RevisionLetter"/>
<xsl:call-template>
</xsl:if>
</xsl:for-each>
....
Don't forget to define the param in your named template.
<xsl:template name=" RevisionRecord">
<xsl:param name=" this-rev-letter " />
...
</xsl:template>
________________________________
Jerry Orabona
Senior Technical Consultant
Agency.com
20 Exchange Place
9th Floor
New York, NY 10005
Phone 212 358 2782
Fax 212 358 2604
www.agency.com
________________________________
-----Original Message-----
From: Levesque, Gary R
[mailto:gary(_dot_)r(_dot_)levesque(_at_)boeing(_dot_)com]
Sent: Wednesday, uly 27, 2005 10:38 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Assign if-test result value to a variable
Newbe question..
I need to assign the result of the following "if-test" statement to a
variable (result is a letter a,b,c, etc). I also need to make the
variable available to the template that I am calling in
(RevisionRecord). I have tried numerous approaches for this but cannot
make it work. Suggestions appreciated.
<xsl:for-each
select="//ApplicationData/Revision_Record[./RevisionLetter!='NEW']">
<xsl:sort select="./RevisionLetter" order="ascending"/>
<xsl:if test="position()=last()">
<xsl:call-template name="RevisionRecord">
<xsl:with-param name="this-letter"
select="."/>
<xsl:call-template>
</xsl:if>
</xsl:for-each>
Thanks in advance.
Gary
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