Thank you Joe and Michael
-----Message d'origine-----
De : Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Envoyé : lundi 25 juillet 2005 11:45
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : RE: [xsl] problem with valid Qnames
You want
<xsl:element name="{$name}">
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Philippe LAPLANCHE
[mailto:philippe(_dot_)laplanche(_at_)horus-si(_dot_)com]
Sent: 25 July 2005 10:26
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] problem with valid Qnames
Hello
I'd like to transform this:
<?xml version="1.0" encoding="UTF-8"?>
<csvFile>
<line>
<value>Nom</value>
<value>Prenom</value>
<value>Sexe</value>
</line>
<line>
<value>Burke</value>
<value>Eric</value>
<value>H</value>
</line>
<line>
<value>Burke</value>
<value>Jennifer</value>
<value>F</value>
</line>
<line>
<value>Burke</value>
<value>Aidan</value>
<value>H</value>
</line>
</csvFile>
Into this :
<data>
<line>
<nom>Burke</nom>
<prenom>Eric</nom>
<sexe>H</nom>
</line>
<line>
<nom>Burke</nom>
<prenom>Jenifer
...
</line>
...
I'm using this stylesheet :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<data>
<xsl:apply-templates select="*"/>
</data>
</xsl:template>
<xsl:template match="line">
<xsl:if test="not(position()=1)">
<line>
<xsl:apply-templates select="value"/>
</line>
</xsl:if>
</xsl:template>
<xsl:template match="value">
<xsl:variable name="pos" select="position()"/>
<xsl:variable name="name"
select="//line[1]/value[$pos]"/>
<xsl:element name="$name"><xsl:value-of
select="."/></xsl:element>
</xsl:template>
</xsl:stylesheet>
But I get an error because $name is not a valid Qname
How do I solve this?
Philippe
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